$\int\left(\frac{5x-1}{x\left(x-3\right)^2}\right)dx$
$\left(6x+5\right)^{\circ\:}=\left(5x-12\right)^{\circ\:}$
$m\left(y+2\right)\:-3\left(y-2\right)$
$\left(x^2+2\right)\left(x-1\right)^3$
$-17+\left|-10\right|$
$12+6x+5-5x$
$\left(x+3y\right)\left(4a-6x\right)$
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