$\tan^2x\left(\csc^2x-1\right)=\cot x$
$\lim_{x\to0}\sqrt{x+3}$
$503+41$
$-\frac{x}{3}=2$
$6\:\frac{1}{6}+12\:\frac{1}{2}$
$\left(-6+4\right)+\left[\left(4+3+-5\right)+\left(-1+1\right)+-5\right]\left[-9+\left(-5+3\right)+10\right]$
$4x^2+12x=18$
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