$47-9x=13+8x$
$\int x+e^x+\pi dx$
$\int_0^2\left(x\sqrt{1+16x^4}\right)dx$
$-\left(13+\left(-4\right)\right)-\left(-12\right)-2+4\left(-1\right)$
$-x^2+10x-9\ge0$
$\left(\frac{2}{3}x+\frac{5}{5}\right)$
$\frac{2x^4-3x^2+x}{x}$
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