$\lim_{x\to-3}\left(2x^4-5x^3+7x\right)$
$-x-12>8$
$98.13-23.85$
$x^3+x+2$
$\frac{secx+tanx+1}{secx+tanx+1}$
$2x+7\ge5$
$9+6b^6+b^{12}$
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