$\lim_{x\to-2}\left(\frac{x^2-x-6}{x-3}\right)$
$16y^2-81x^4$
$-95\:+4$
$x+8\ge-7$
$4x^2-3x=-28$
$\frac{d^2}{dx^2}\left(\left(5x^2-1\right)\left(2x^3+x\right)\right)$
$\frac{1}{\sqrt{\left(x^2+a^2\right)}}$
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