$\lim_{x\to+\infty}\left(\frac{ln\left(1+4e^x\right)}{\sqrt{1+4x^2}}\right)$

$4x^2-32x-64$

$4\cdot x=36$

$\frac{4x^2+4x+7}{x^2+1}$

$4cosx-1=2sinxtanx$

$sin\left(arccos\left(\frac{3}{4}\right)-arctan\left(\frac{1}{2}\right)\right)$

$45g^3+34g^2+g-1+12g^5+27g^4+76g+45$