$10-11\sin\left(c\right)=6$
$\frac{3x-6}{3}=\frac{x+6}{2}$
$2cos^2xtanx$
$1-2sin^2x=2sinxcosx$
$\left(a-3b\right)^6$
$\left[16-\left(-11\right)\right]-18$
$\:\:\left(x+1+2\sqrt{x}\right)\left(x+1-2\sqrt{x}\right)+\left(x+1\right)^2\:\:$
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