$\left(3\right).\left(-2\right)+\left(-2\right).\left(-3\right)+4$
$f\left(x\right)=x^2+3x$
$\left(x+a\right)\left(x+g\right)$
$6^2\cdot12^{-2}$
$\frac{15x^5}{3} x^2$
$\frac{-4x^5+6x+8}{2x^2}$
$\left(12m+4n\right)\left(12m-4n\right)$
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