$5\:x\:>\:25$
$\left(x^2+2x+4\right)^2$
$\left(2m^3+3n^9-4d^6\right)^2$
$x^2-4x-320$
$\frac{3x^2a}{x}-5xa-\frac{7x^{-2}}{x^3a^{-1}}$
$\frac{d}{dx}\left(x^x\right)ln\left(\left(x+1\right)^2\left(x-2\right)\left(x^2+3\right)\right)$
$3\cdot2^4-5\cdot2^2-1$
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