$\left(x+3\right)\left(3x-4\right)$
$x^2+6x-5=0$
$-9\cdot\left(-9+6\right)$
$x+4y=7$
$2^{x+2}-6\cdot2^{x+1}=-64$
$0.81g^2-\left(f+g\right)^2$
$\frac{dy}{dx}=3sqrt\left(xy\right)$
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