$\sec^2\left(5x\right)=\frac{1}{3}$
$\left(-3x+9\right)-\left(-2x^2+6x\right)$
$43,7+70,2+59,8$
$\frac{2b^3x^2y}{3};\:b=-1;\:x=\frac{3}{5};\:y=8$
$6x-10=20$
$7x^2\left(2x^4+6x^3-4x^2\right)$
$\left(x^2-5\right)\left(x+4\right)=x^3$
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