$a^6b^3+1$
$\left(2xy^2+\frac{4}{a}\right)dx-2\left(3-x^2y\right)dy=0$
$\left(-13\right)\cdot\left(-2\right)\cdot4$
$\lim_{x\to\infty}\left(\frac{9x-1}{sinx}\right)$
$\left(3x^2+x^3\right)^3$
$\sec2\left(x\right)-\tan2\left(x\right)$
$4x^2-4x\le\:-1$
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