$\int\left(4v^4e^{2v^5}\right)dv$

$\frac{x^2}{4}+x+1$

$\int\:\frac{3}{x^2-4x+3}dx$

$\frac{3+x^3-5x}{x^2+x}$

$-8+2-6+5-2+2\left(-3\right)$

$\frac{\frac{2x+2y+1}{x+y+3}}{y}$

$\frac{\left(4\left(1\right)^2\left(3^3\right)\right)^4}{\left(2\left(1\right)^3\left(3\right)^2\right)^3}$