$5x+4=4$
$27\left(-27\right)$
$\lim_{x\to4}\left(\frac{24}{x}-2x+2\right)^3$
$\frac{7x^5-22+3x^3-2}{-x+2}$
$m^2+m+8$
$3x+5>x-1$
$\lim_{x\to4}\left(\frac{x^3+48x-12x^2-64}{x^2-16}\right)$
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