$\left(2x+1\right)^2+\left(3x-4\right)-10x^2+6x$
$6x+3y=15$
$\lim_{x\to\infty}\left(x^{0.999999}\right)$
$\left(n-4\right)x^2+2\left(n+3\right)x+3n-14=0$
$725-303+18$
$48\cdot27$
$\int4x\:\sqrt{x^2+2x}dx$
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