$\frac{\left(x^2-5x-24\right)}{\left(x+3\right)}$
$\frac{3}{x-2}>\:2$
$y'-x^3y=4x^3$
$\left(x\:-\:5\right)\left(x\:-\:7\right)$
$8x^2+7x-x+2$
$a^2-10;\:a=3;\:b=-2;x=-1$
$sen^4x-cos^4x=0,\:5$
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