$-3\left(3x\:\:-\:2\right)\:-\:1\:$
$8x^33y^9$
$4-u^2z^6$
$.25x+8y=15$
$\frac{6x^3+23x^2-38x-15}{3x+1}$
$\frac{dy}{dx}=\frac{x\cdot y^2}{1+z}$
$3x+5>x+7$
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