$19x+16\le-10+14x$
$x^3-4x^2-5x.\:$
$\lim_{x\to-\infty}\left(6+\frac{2x}{x^2+3}\right)$
$30t\:+\left(-5t\right)+9t-17t-\left(-8t\right)$
$2x-3\ge x+2$
$\:4x+12=x+12$
$\lim_{x\to-\infty}\left(\frac{x^8-23}{x-9}\right)$
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