$\frac{d}{dx}y=\frac{2senxcosx}{\cos2x}$
$3x^2+4x-3$
$\sqrt[5]{160x^8}y^5$
$24x^2-36x+20$
$\frac{d^2}{dx^2}\left(y=x^2\left(x^2+5\right)^2\right)$
$\frac{4}{5p^{-2}m^{-7}}$
$2x+6>4$
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