$\left(x+3y+3z\right)^2$
$4=-5+y$
$cos^2x-3sen^2x$
$6z+4y+2x=-12$
$\left(7xsen\left(x\right)-4y\right)dx-4xdy=0$
$13b-18c+15b+17c-17c-13a+8b-9a$
$\frac{3\:sen\left(x\right)+\:4\:cos\left(x\right)}{sen\left(x\right)\:cos\left(x\right)}=3\:sec\left(x\right)\:+4\:csc\left(x\right)$
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