$\left(xy-2x^2\right)y'=\left(\frac{1}{2}\right)y^2-yx$
$\lim_{x\to-\infty}\left(\frac{7^x+19^x}{2}\right)^{\frac{1}{x}}$
$3x^3-13x^2+2x+8$
$x^2-7x+\frac{7}{2}^2$
$3\left(x+6\right)\left(x+6\right)$
$\frac{2csc\left(2x\right)}{sec\left(x\right)}$
$4a+3a$
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