$-\frac{1}{tan^2x}=cot^2x$
$\int9tan^2\left(x\right)sec^2\left(x\right)dx$
$\left(3a+d\right)^3$
$\int m d x$
$6a+12b$
$\left(13+2x\right)\left(13+2x\right)$
$\sqrt{\left(2x+3\right)^2}$
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