$\int7e^{6x+1}dx$

$\lim_{x\to2}\left(\frac{x-7}{\left(x-2\right)^2}\right)$

$\left(\sqrt[4]{x^3y^3}\right)^{12}\:\left(\sqrt{xy}\right)^6$

$4ab+2ba-3ab-5ab$

$7+\left(4-\left(6-8\right)+3\right)$

$2x-1+2x-4+y$

$\lim_{x\to\infty}\:\left(6+x^7\right)\left(\frac{1}{\ln\left(5x^2+1\right)}\right)$