$\int\frac{5}{\left(3x+1\right)\left(1+\ln\:\left(3x+1\right)\right)^2}dx$
$\frac{1}{4}j+\frac{1}{4}j$
$3x^3-6x^2-9x$
$2^{3}+3^{2}-\sqrt{100}$
$\left(x-6\right)\left(x-9\right)\ge0$
$\int2x\ln3xdx$
$\sqrt{2x^2}\cdot\sqrt{6x}$
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