$\frac{z^{-4}}{z^2}$
$\lim_{n\to\infty}\left(\frac{2^n}{2^{2^n}}\right)$
$\left(3x+2xy\right)^2$
$16^4+20^2+49$
$5x-7^2-5x-75x+7+4$
$\frac { - t ^ { 3 } + 3 t ^ { 2 } - 9 t } { 4 }$
$10^6\cdot10^3$
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