$2x^2+16x+12$

$\lim_{x\to0}\left(\frac{7x}{\cos\left(x\right)-3x+1}\right)$

$7\frac{3}{4}+3\frac{5}{6}-1\frac{3}{4}$

$\int\left(2x-1\right)^3dx$

$\left(\sec^2\left(x\right)-1\right)\cdot\cos^2\left(x\right)=\sin^2\left(x\right)$

$\frac{dy}{dx}=2x-3y-1$

$y'=\frac{x-1}{y^2\:},\:y\left(0\right)=2$