$y=\left(\sec\left(x\right)\right)^{\tan\left(-1x\right)}$
$x^2+2x+4=7$
$\cos\left(x\right)^2-2\cos\left(x\right)+3$
$7-5x<2x-7$
$\left(18\:\cdot2500\right)\:+\:\left(24\:\cdot2500\right)$
$5\left(5x+4y\right)\:\:\:\:5\left(5x-4y\right)$
$\int\frac{x-5}{x^2-x-2}dx$
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