$\int_{-1}^3\left(10x\right)dx$
$3y^2-y+7y-y^2$
$2025-18$
$\frac{dy}{dx}=x\left(x-2\right)$
$\frac{dy}{dx}tany$
$\left(x+1\right)\cdot\left(-2x^2\right)$
$\frac{\tan\:\left(26^{\circ\:}\right)+\tan\:\left(4^{\circ\:}\right)}{1-\tan\:\left(26^{\circ\:}\right)\tan\:\left(4^{\circ\:}\right)}$
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