$\sqrt{x}+5=3$
$-3u-4=5$
$w^2-16w+10$
$\lim_{x\to1}\left(\frac{x^3-3x+2}{1-\sqrt{x}}\right)$
$|-9|$
$\frac{2x^3-x+4}{x+5}$
$\frac{dy}{dx}=\left(7-8x\right)y^2$
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