$5+4-\left|5-\left(6+5-8\right)+\left(9-1+4\right)\right|$
$6\left(3a\right)^1\left(4b^2\right)^5$
$40x^5y^2+7x^4y^6$
$\frac{x^5+x^4-6}{x^3-4x}$
$\lim_{x\to\infty}\left(\frac{e^{3x+2}}{x^2}\right)$
$3\left(x^2+x\right)$
$\left(w^2+7y^5\right)\left(w^2-7y^5\right)$
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