$38y^0$
$\:3x^2+3x-6$
$3+5.8$
$\log_x\left(4x+5\right)=2$
$\lim_{t\to-1}\left(\frac{ln\left(3+2t\right)}{t+1}\right)$
$arccos\:\left(x^2-2x+2\right)=0$
$\lim_{x\to0}\left(\frac{12e^x-12-12x-6x^2}{x^3}\right)$
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