$-7^5$
$\lim_{x\to0}\left(\frac{5x^3-6x}{7x^3+7}\right)$
$\lim_{x\to\:\infty}\sqrt[3]{x\left(x+1\right)}$
$\int4\tan^3\left(\frac{x}{5}\right)\sec^3\left(\frac{x}{5}\right)dx$
$\int\frac{2x}{x^3-x}dx$
$\int\frac{\cos\left(x\right)}{4-\sin\left(x\right)}dx$
$\tan\left(x\right)\cdot\left(\tan\left(x\right)-2\right)=6$
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