$\left(6u^2+5v\right)^3$
$\int\:\frac{2x-1}{\left(x+1\right)^2\left(x+2\right)^2}dx$
$\frac{x^2-2x+4}{x+3}$
$\left(\:cos\:\left(h\right)\:x\right)^2$
$x^2+3x+4x$
$\left(-7x+6\right)\left(7x+6\right)$
$12x^2-62x+70$
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