$\frac{4}{x-2}+\frac{7}{x+1}=3$
$\left(x^3\cdot x^{-2}\right)^4$
$\left(2a^2b^{-1}\right)^2$
$x+2>\:5$
$\lim_{x\to\infty}\left(2\:cos\:x\:+tan\:x\right)$
$x'=3x$
$\left(x+3y-2\right)-\left(2y-x+3z\right)+\left(4z-3x+2y\right)$
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