$\left(3a^3\right)+4b^4\left(3a^3-4b^4\right)$
$\frac{x}{4}+\frac{8}{x}=3$
$-8-14-7-90$
$2cos^2x-1-cosx=0$
$\cos^2+\cos^2\sin^2$
$2x^{2}-9x-5=0$
$-7>2x-6$
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