$-\left|6\right|$
$\frac{\left(4x^3-14x^2-7x-4\right)}{x-4}$
$15-4g-8-6$
$0=\frac{1}{10}\left(4x^3-42x^2+120x\right)$
$\sqrt{29}\cdot\sqrt{29}$
$\left(w-6\right)\left(w+9\right)$
$3x^2-12x=12x$
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