$+17-7+4+2-1+18-6$
$\frac{d}{dx}\:\sqrt[3]{\frac{\left(4x+1\right)\left(x+3\right)^2}{\left(x^4+5\right)\left(x+8\right)}}$
$\frac{dy}{dx}=\tan^2\left(2x\right)$
$6-2x-4\left(2x+1\right)$
$\:-2x+14=0$
$m^2-5m-1$
$4x^2+60x+90$
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