$x\left(3x+10\right)=77$
$\left(3a+5c\right)\left(3a-5c\right)$
$\frac{x^5-1}{2x^2-5}$
$\frac{1}{\csc^3\left(x\right)}$
$\left(\frac{-48ab^{-3}}{-6a^3b^5}\right)^{-1}$
$z^2\:-\:4\:z\:+\:5\:=\:0$
$\frac{dy}{dx}=27e^{3x}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!