$6\left(3x-4\right)$
$x^2+y^3=4$
$x^5-2x^4-6x^3+12x^2+x-2$
$\left(-7x\:+\:1\right)\:+\:\left(2x\:-\:11\right)$
$\frac{d}{dx}\:3x^{\sqrt{x}}$
$5x^2-17x+3=-4x-5$
$6\cdot\left(-3\right)\cdot\left(-5\right)\cdot\left(-3\right)$
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