$\int\frac{\left(3x+6\right)}{3x^3+2x^2-3x}dx$
$-\:54\:+\:786\:$
$6x^3y^3\cdot2x^2y$
$\frac{dy}{dx}=\frac{y^3}{x^3}$
$\int\frac{1}{3+5x}dx$
$x^2+4x-5\ge0$
$x^2\cdot m^2x^{m-2}$
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