$x+2=3x+8$
$3y^{-3}\:x\:4x^2$
$\tan\left(-405\right)$
$\frac{dy}{dx}=\frac{xy-3x}{x^2-1}$
$-\sqrt{4}$
$2.6+0.6$
$3x+5\le4x+3$
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