$10x-50=90$
$\frac{\left(\sin^4\:x-\cos\:^4x\right)}{\left(\cos^2\:\:x\right)}$
$-8\sin\left(x\right)\:+\:5=1$
$x^3+3x^2+6x+18$
$\frac{1-\sin y}{\cos y}=\frac{\cos y}{1+\sin y}$
$-5t^3+2t^3$
$\frac{27x^5}{42x}$
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