$\frac{\cos\left(x\right)\cdot\sin^2\left(x\right)+\cos^3\left(x\right)}{\sin\left(x\right)}$
$\frac{\sin^2}{\csc}=\sin^3$
$\left(5x+15\right)$
$\log\left(10x\right)-\log\left(5\right)=\log\left(4\right)+\log\left(6\right)$
$x-14=-21$
$\left(2m^2-4m+5\right)\left(m^2-3m+10\right)$
$\frac{5}{x}-\frac{1}{3}=\frac{x}{1}$
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