$6a^{5}+5\right)\left(11a^{5}-4$

$\frac{\tan\left(a+b\right)-\tan\left(b\right)}{1+\tan\left(a+b\right)\cdot\tan\left(b\right)}$

$\frac{9x^{-3}-81x}{x^2+3x}$

$6=-\left|6\right|$

$3x-1\le5x+7$

$-4<=sqrt\left(3x^2+9x\right)$

$\left(xy+x\right)=\left(x^2y^2+x^2+y^2+1\right)y'$