$\lim_{x\to3}\left(\frac{2-x}{x-3}\right)$
$6x^2-60x+36=0$
$1+\sec^{2}\left(\theta\right)\left(1-\sin^{2}\left(\theta\right)\right)$
$\left(-1\right)^3-\left(-3\right)^2\left(-2\right)-1\left(1-2\right)^3+3-2\left(-1\right)+4+3\left(-2\right)-\left(2\right)\left(-1\right)$
$2x^3-3x^2+5x-\frac{7}{x-2}$
$r^2+12=7r$
$\int\frac{x^{4}+2x^{2}-x+9}{x^{3}+2x^{4}}dx$
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