$7\left(2x-1\right)-3=6+6x$
$16-5c+7c+3$
$\int\frac{1}{\left(3+x\right)^2\left(5+2x\right)}dx$
$x^2\:+\:4y^2=4$
$\frac{1}{2}\sqrt{y}+2\sqrt{y}$
$x+y+z=12$
$144x^4-49y^2$
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