$1\cdot25\cdot10$
$8x^2-48x+64$
$x^3-19x+30$
$\left(2x^2\:y\right)^2$
$3x^2-3x<\:2x^2+4$
$\left(\sec a-\tan a\right)^2=\frac{1-\sin a}{1+\sin a}$
$\frac{a^2b}{5}-4ab^2+\frac{7ab^2}{5}-\frac{10a^2b}{11}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!