$\int\left(\frac{\left(ln\left(x\right)-1\right)^2}{x}\right)dx$

$\frac{1}{x-4}-1+\frac{1+ln\left(\left(x-4\right)^x\right)-4ln\left(x-4\right)}{x-4}$

$\left(b^{n+3}-b^{-3}\right)^2$

$\int\left(\frac{-5}{6+9x}\right)dx$

$\left(27\cdot13\right)+\left[16\cdot\left(-6\right)\right]-\left[74\cdot\left(-58\right)\right]$

$\frac{5x}{x}$

$x^2+8x+30$