$\int\frac{\left(x+1\right)^2}{e^x}dx$
$-\left(3-9\left(1-3+\left(8+2-1\right)-\left(2-5\right)-13\right)+4-3\right)$
$8y^2-18$
$\frac{dy}{dx}=-\frac{xy}{1+y^2}$
$\left(\frac{a^6}{z^3}\right)^2$
$\frac{-80}{20}$
$81x^2-18x+1$
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