$\frac{88}{4}$
$x+4=-16$
$\lim_{x\to2}\left(\frac{x^2+x-6}{x^3-x^2-8x+12}\right)$
$-7-4-11-4-2-7-4-5-8$
$17-4x\le-6x+10$
$\left(5x+3y+z\right)^2$
$\left(-1-a\right)^3$
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